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3 votes
Determine whether the sequence converges or diverges. If it converges, give the limit.

11, 22, 44, 88, ...

User Xoppa
by
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2 Answers

3 votes

Answer:

Diverges

Explanation:

The given sequence is:

11, 22, 44, 88,.....

Now,
a_(1)=11=2^0{*}11,


a_(2)=22=2^1{*}11,


a_(3)=44=2^2{*}11,


a_(4)=88=2^3{*}11

Thus,the nth term will be:
a_(n)=2^(n-1){*}11.

Now, as
\lim_(n \to \infty) a_n, then


\lim_(n \to \infty) a_n=2^(n-1){*}11=+{\infty}

Since, as
n{\rightarrow}{\infty},
a_(n){\rightarrow}+{\infty}, thus the given sequence diverges.

User Assad Ullah
by
8.4k points
1 vote
The sequence is a geometric sequence with a common ratio of 2. since the common ratio is greater than 1, the sequence diverges.
User Raghumudem
by
8.7k points
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