Question

1.If a 40 kg person is accelerating at 10 m/s2, then the force acting on him or her is 400 N

A. true or B.false
2.How much force is needed to make a 60 kg object accelerate at a rate of 2.0 m/s2?
A. 62 N
B.62 kg
C.120 N
D.120 kg
3.What is the acceleration of a 30 kg object when 180 N of force is applied to it?
A.6.0 m/s2
B.60 m/s2
C.210 m/s2
D.5,400 m/s2
4.Which of the following equations show how you would solve for mass if you knew the force acting on an object & the acceleration of an object?
A.m=f/a
B.m= fa
C.m=a/f
D.m=f-a

Answer 1

Answer: 1) The given statement is true.

2 .The correct answer is option C.

3.The correct answer is option A.

4.The correct answer is option A.

Step-by-step explanation:

1. Mass of the person = m = 40 kg

Rate of acceleration of person = a =
`10 m/s^2`

Force on the person =
`F=mass* acceleration = 40 kg* 10 m/s^2=400 N`

True, the force acting on him or her is 400 N.

2.Mass of an object ,m= 60 kg

Rate of acceleration of an object ,a=
`a=2.0 m/s^2`

Force required:

`F=m* a=60 kgtimes 2.0 m/s^2=120.0 N`

Hence, the correct answer is option C.

3. Mass of an object ,m= 30 kg

Force applied ,F = 180 N

Let rate of the acceleration be = a

`F=m* a`

`a=(180 N)/(30 Kg)=6.0 m/s^2`

Hence, the correct answer is option A.

4. If we know the force acting on an object along with acceleration of an object.

From the formula: F= ma

Mass can be determined by:

`m=(F)/(a)`

Hence, the correct answer is option A.

Answer 2

In all of the questions, we apply Newton's second law that:
Force = mass x acceleration
1) A. True

2) C, 120 N; F = 60 x 2 = 120N

3) A, 6 m/s²; a = F/m = 180/30 = 6

4) A; F = ma → m = F/a