Question

B) Calculate the area of the trapezium

5.2cm
Not drawn accurately
6cm
4.5cm
10.8cm

Answer 1

Explanation:

`\underline{ \underline{ \text{Given}}} :`

• Height ( h ) = 4.5 cm
• Base 1 ( b ) = 5.2 cm
• Base 2 ( b ) = 10.8 cm

`\underline{ \underline{ \text{To \: find}}} :`

• Area of the given trapezium

`\underline{ \underline{ \text{Solution}}} :`

`\boxed{ \sf{Area \: of \: a \: trapezium = (1)/(2) h \: (b_(1) + b_(2))}}`

Plug the known values and then simplify !

⟶
`\sf{ (1)/(2) * 4.5 * (5.2 + 10.8)}`

⟶
`\tt{ (1)/(2) * 4.5 * 16}`

⟶
`\tt{36 \: {cm}^(2) }`

`\red{ \boxed{ \boxed{ \tt{Our \: final \: answer : \boxed{ \underline{ \bold{ \tt{36 \: {cm}^(2) }}}}}}}}`

Hope I helped ! ツ

Have a wonderful day / night ! ♡

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Answer 2

The area of the trapezium is 25.2 cm².

To calculate the area of a trapezium, we can use the formula:

Area = (a + b) * h / 2

where a and b are the lengths of the parallel sides and h is the height.

Given that AB = 5.2 cm, BC = 6 cm, and height = 4.5 cm, we can substitute these values into the formula:

Area = (5.2 + 6) * 4.5 / 2

Area = 11.2 * 4.5 / 2

Area = 50.4 / 2

Area = 25.2 cm²

The probable question may be:

b) Calculate the area of the trapezium

AB=5.2cm

BC= 6cm

height=4.5cm

CD=10.8cm