Question

What is the quotient: (64y3 + 20y2 _ 28y) … 4y ?

16y2 _ 5y + 7

16y3 + 5y2 _ 7y

16y2 + 5y _ 7

16y2 _ 5y _ 7

Answer 1

option:C

Explanation:

The quotient is a quantity produced by the division of two numbers.

here we are given a polynomial
`64y^3+20y^2-28y` ;we have to divide it by
`4y`

We know that
`64y^3+20y^2-28y` it could also be written as
`4y(16y^2+5y-7)`

Now on dividing
`4y(16y^2+5y-7)` by
`4y` we get that
`4y` term cancels in the numerator and denominator and we are left with the term
`16y^2+5y-7` ; which will be a quotient.

Hence, option C is correct.

Answer 2

We divide each term by 4y
64y³ / 4y = 16y²
20y² / 4y = 5y
-28y / 4y = -7
The quotient is
16y² + 5y -7
The third option is correct