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What is the sum of the arithmetic sequence 6, 14, 22, if there are 26 terms
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What is the sum of the arithmetic sequence 6, 14, 22,
if there are 26 terms

User Rajesh Deshpande
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1 Answer

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Sum of nth term of arithmetic sequence is given by Sn = n/2[2a + (n - 1)d]
Here, a = 6, n = 26 and d = 14 - 6 = 8
S26 = 26/2[2(6) + (26 - 1)8] = 13[12 + 25(8)] = 2,756
User Pete Doyle
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