Question

For which of the following equations is (3, - 4) a solution?3x - 4y = 02 x + 2y = - 23y - 2x = 17 3x = 2y + 1

Answer 1

`\begin{gathered} \text{Given} \\ \text{Ordered pair }(x,y)=(3,-4) \end{gathered}`

Substitute x = 3, and y = -4, to the following choices and see if it holds true

`\begin{gathered} 3x-4y=0 \\ 3(3)-4(-4)=0 \\ 9+16=0 \\ 25\\eq0 \\ \\ 2x+2y=-2 \\ 2(3)+2(-4)=-2_{} \\ 6-8=-2 \\ -2=-2 \\ \\ 3y-2x=17 \\ 3(-4)-2(3)=17 \\ -12-6=17 \\ -18\\eq17 \\ \\ 3x=2y+1 \\ 3(3)=2(-4)+1 \\ 9=-8+1 \\ 9\\eq-7 \end{gathered}`

Out of the four choices, the equation that satisfies (3,-4) as a solution is 2x + 2y = -2