Question

Calculate the mass of KHC8H4O4 that reacts with 20 ml of 0.1 Monday NaOH.

Answer 1

The mass of KHC8H4O4 that reacts with 20 mL of 0.1 M NaOH is 0.40844 g. This is calculated by finding that 0.002 moles of NaOH will react with an equivalent number of moles of KHC8H4O4, then multiplying by the molar mass of KHC8H4O4.

Step-by-step explanation:

To calculate the mass of potassium hydrogen phthalate (KHC₈H₄O₄) that reacts with 20 mL of 0.1 M NaOH, we will first determine the number of moles of NaOH. Since molarity (M) is equal to the number of moles of solute per liter of solution, we can calculate the moles of NaOH as follows:

• Number of moles of NaOH = Volume (L) × Molarity (M) = 0.020 L × 0.1 M = 0.002 moles NaOH

The balanced chemical equation for the reaction between KHC₈H₄O₄ and NaOH is:
KHC₈H₄O₄ + NaOH → NaKC₈H₄O₄ + H₂O

According to the balanced chemical equation, one mole of KHC₈H₄O₄ reacts with one mole of NaOH. Therefore, 0.002 moles of NaOH will react with 0.002 moles of KHC₈H₄O₄. Next, we find the mass of KHC₈H₄O₄:

• Molar mass of KHC₈H₄O₄ = 204.22 g/mol
• Mass of KHC₈H₄O₄ = Number of moles × Molar mass = 0.002 moles × 204.22 g/mol = 0.40844 g

Answer 2

Obviously only one of the H's was replaced as the product showed one mole of water So the ratio is 1 to 1.Moles of NaOH used Molarity x volume = 0.1 x0.015(L) = 0.0015 moles
Mass of acid used is 0.0015 x 204 = 0.306g
moles MM

hopefully this helps