Question

- What is the equation of the circle with center (-4,-1) and radius 3? O (x + 4)² + (y + 1)² = 9 O (x +4)² + (y + 1)² = 3 O (x – 4)² + (y - 1)² = 3 O (x – 4)²+ (y - 1)² = 9 -

Answer 1

(x + 4)² + (y + 1)² = 9

Explanation:

The general equation for a circle is given below:

`\mleft(x-h\mright)^2+\mleft(y-k\mright)^2=r^2\text{ where }\begin{cases}r=\text{radius} \\ (h,k)=\text{center}\end{cases}`

Given a circle with center (-4,-1) and radius 3, its equation is:

`\begin{gathered} \mleft(x-(-4)\mright)^2+\mleft(y-(-1)\mright)^2=3^2 \\ \implies(x+4)^2+(y+1)^2=9 \end{gathered}`

The correct option is the first one.