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Which equation is a point slope form equation for line AB ?

A.y−2=−2(x+6)y−2=−2(x+6)

B.y−6=−2(x+2)y−6=−2(x+2)

C.y−2=−2(x+2)y−2=−2(x+2)

D.y−2=2(x+2)

Which equation is a point slope form equation for line AB ? A.y−2=−2(x+6)y−2=−2(x-example-1
User Dark Cyber
by
8.1k points

2 Answers

5 votes

Answer: the answer is B... short answer but correct

Explanation:

User Jittakal
by
8.1k points
6 votes

Step 1

Find the equation of the line AB

we know that

the equation of the line into point-slope form is equal to


y-y1=m(x-x1)

Let


A( -2,6)\\B(2,-2)

Find the slope m

we know that

the slope between two points is equal to


m=((y2-y1))/((x2-x1))

substitute


m=((-2-6))/((2+2))


m=((-8))/((4))


m=-2

with the slope m and point A find the equation of the line AB


y-6=-2(x+2)

or

with the slope m and point B find the equation of the line AB


y+2=-2(x-2)

we will proceed to verify each case to determine the solution of the problem

Step 2

Verify case A

Case A)
y-2=-2(x+6)

the slope of the line is
m=-2

but the point
(-6,2) -----> not lie on the line AB (see the graph)

therefore

the case A is not the solution

Step 3

Verify case B

Case B)
y-6=-2(x+2)

the slope of the line is
m=-2

and the point
(-2,6) -----> is the point A

therefore

the case B is a solution

Step 4

Verify case C

Case C)
y-2=-2(x+2)

the slope of the line is
m=-2

but the point
(-2,2) -----> not lie on the line AB (see the graph)

therefore

the case C is not the solution

Step 5

Verify case D

Case D)
y-2=2(x+2)

the slope of the line is
m=2 -----> the slope is not equal to the slope AB

and the point
(-2,2) -----> not lie on the line AB (see the graph)

therefore

the case D is not the solution

the answer is

The equation
y-6=-2(x+2) is a point-slope form of the line AB


User Hassan Ahmadi
by
8.4k points
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