Question

Can you help me with this. I need equation and angle

Answer 1

The equation for a simple harmonic motion (SHM) is given by:

`y=A\cdot\sin (wt+\alpha)`

Where A is the amplitude, alpha is the initial phase and the period is given by T = 2π/omega.

So, for A = 2, T = 1.5 and alpha1 = π/2. we have:

`\begin{gathered} \omega=(2\pi)/(T)=(2\pi)/(1.5)=(4\pi)/(3) \\ \\ y_1=2\cdot\sin ((4\pi)/(3)t+(\pi)/(2)) \end{gathered}`

For A = 2, T = 1.5 and alpha = π/3, we have:

`y_2=2\sin ((4\pi)/(3)t+(\pi)/(3))`

Now, adding both oscillations, we have:

`\begin{gathered} y=y_1+y_2 \\ y=2(\sin ((4\pi)/(3)t+(\pi)/(2))+\sin ((4\pi)/(3)t+(\pi)/(3))) \end{gathered}`