Question

A team of dogs pulls a sled across the snow. The weight of the loaded sled is 2,200 N. The coefficient of friction is 0.15. How hard must the dogs pull so that their effort just equals the frictional force? 220 N 330 N 15,000 N 34 N

Answer 1

.. The weight of the loaded sled is 2200 N. The coefficient of friction is 0.15. How hard must the dogs pull so that their effort just equals the frictional force? ... to move after the light changes from red to green A team of dogs pulls a sled across the snow. ... 2) pulling force of dogs fL = us N = 0.15 x2200 = 330 N

Answer 2

Answer: The dogs must pull the sledge with a force of 330 N.

Explanation:

Frictional force is described as the force generated by the two surfaces when they are in contact and slide against each other.

Mathematically,

`f=\mu N`

where, f = frictional force

`\mu =\text{coefficient of friction}`

N = Normal force

Given: N = 2200 newtons

`\mu=0.15`

Putting the values, in the above equation, we get:

`f=0.15* 2200N=330N`

Block Diagram of normal force is shown in the given image.