Question

What is the centripetal force needed to keep a 3.0 kg mass moving in a circle of radius 0.50 m at a speed of 8.0 m/s

Answer 1

Centripetal acceleration = v²/r = 8²/0.50 = 64/0.50 = 32

Centripetal force = mass * acceleration = 3 * 32 = 96 Newton

So, your answer is 96 Newton

Answer 2

Answer : The centripetal force needed is, 384 N

Solution :

Formula used for centripetal force is,

`F_c=(m* v^2)/(r)`

where,

`F_c` = centripetal force

m = mass of an object = 3 Kg

r = radius of path

v = velocity or speed of an object

Now put all the given values in the above formula, we get the centripetal force.

`F_c=(3Kg* (8m/s)^2)/(0.5m)=384Kg\text{ m }s^(-2)=384N`

Therefore, the centripetal force needed is, 384 N