205k views
0 votes
The length of a rectangle is 5 feet more than twice the width. The perimeter is 130 feet. Find the dimensions.

User Marita
by
8.6k points

1 Answer

6 votes
So,

The problem tells us that the length of the rectangle is 5 feet more than twice the width.
Mathematically:
length = 5 + 2width
l = 5 + 2w


We know that the perimeter is 2l + 2w.
2l + 2w = 130

2(5 + 2w) + 2w = 130

Distribute
10 + 4w + 2w = 130

Collect Like Terms
10 + 6w = 130

Subtract 10 from both sides
6w = 120

Divide both sides by 6
w = 20

The width is 20.


Since
l = 5 + 2w

Substitute
l = 5 + 2(20)

Multiply
l = 5 + 40

Collect Like Terms
l = 45

The length is 45.

Check
2l + 2w = 130

2(45) + 2(20) = 130

90 + 40 = 130

130 = 130

Width: 20 ft.
Length: 45 ft.
User AlanSE
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories