Question

How many grams are there in 7.5 X10^23 molecules of H2SO4?

Answer 1

Answer : The mass of
`H_2SO_4` are, 117.6 grams.

Explanation :

First we have to calculate the moles of
`H_2SO_4`.

As,
`6.022* 10^(23)` molecules of
`H_2SO_4` present in 1 mole of
`H_2SO_4`

So,
`7.5* 10^(23)` molecules of
`H_2SO_4` present in
`(7.5* 10^(23))/(6.022* 10^(23))=1.2` mole of
`H_2SO_4`

Now we have to calculate the mass of
`H_2SO_4`.

`\text{Mass of }H_2SO_4=\text{Moles of }H_2SO_4* \text{Molar mass of }H_2SO_4`

Molar mass of
`H_2SO_4` = 98 g/mole

`\text{Mass of }H_2SO_4=1.2mole* 98g/mole=117.6g`

Therefore, the mass of
`H_2SO_4` are 117.6 grams.

Answer 2

Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles.

7.5 X10^23 molecules of H2SO4 ( 1 mol / 6.022x10^23 molecules ) (98.08 g / 1 mol ) = 122.15 grams H2SO4