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How many grams are there in 7.5 X10^23 molecules of H2SO4?

User Tuinstoel
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2 Answers

3 votes

Answer : The mass of
H_2SO_4 are, 117.6 grams.

Explanation :

First we have to calculate the moles of
H_2SO_4.

As,
6.022* 10^(23) molecules of
H_2SO_4 present in 1 mole of
H_2SO_4

So,
7.5* 10^(23) molecules of
H_2SO_4 present in
(7.5* 10^(23))/(6.022* 10^(23))=1.2 mole of
H_2SO_4

Now we have to calculate the mass of
H_2SO_4.


\text{Mass of }H_2SO_4=\text{Moles of }H_2SO_4* \text{Molar mass of }H_2SO_4

Molar mass of
H_2SO_4 = 98 g/mole


\text{Mass of }H_2SO_4=1.2mole* 98g/mole=117.6g

Therefore, the mass of
H_2SO_4 are 117.6 grams.

User Interstar
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7.5k points
5 votes
Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles.

7.5 X10^23 molecules of H2SO4 ( 1 mol / 6.022x10^23 molecules ) (98.08 g / 1 mol ) = 122.15 grams H2SO4
User Ista
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7.0k points