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What depth of sea water (in m) creates a pressure of 1.83 atm?

User Phil Peace
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1 Answer

18 votes
18 votes

Given:

Pressure = 1.83 atm

Let's determine the depth of sea water that creates the given pressure.

Apply the formula for pressure on a liquid:


P=\rho gh

Where:

P is the pressure in Pa.

Where:

1 atm = 101325 Pa

1.83 atm = 1.83 x 101325 = 185424.8 Pa

ρ is the density of sea water = 1000 kg/m³

g is acceleration due to gravity = 9.8 m/s²

h is the depth.

Rewrite the formula for h and solve:


\begin{gathered} h=(P)/(\rho g) \\ \\ h=(185424.8)/(1000*9.8) \\ \\ h=(185424.8)/(9800) \\ \\ h=18.92\text{ m} \end{gathered}

Therefore, the depth of sea water which creates the pressure given is 18.92 m

ANSWER:

18.92 m

User Saggio
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