160k views
1 vote
geoff says that changing the value of m while leaving b unchanged in f(x)=mx+b has no impact on th intercepts of the graphs. Marcus disagrees with this statement. Who is correct? explain your reasoning.

User Mumino
by
6.3k points

2 Answers

1 vote

Answer: Marcus is correct, changing the value of m and leaving b unchanged has impact in the x-intercept.

Explanation:

The linear equation is

f(x) = m*x + b

now, m is the slope and b is the y-intercept, so if we cahenge m, b remains unchanged, so the y-intercept does not change.

now, the x-intercept is when f(x) = 0 = m*x + b

so the x-intercept is = -b/m

We can see that the x-intercept depends inversilt with m, so chaging m will change the x-intercept.

User Fsevenm
by
7.3k points
3 votes
I would agree with Marcus' stand that the statement is wrong. Changing the value of m while leaving b unchanged in f(x)=mx+b would surely have an impact on the intercepts specifically the x intercept. Changing the value m would correspond to a change to the x-intercept as well.
User Alexander Revutsky
by
7.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.