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Given a spring which has been compressed by 16.08 m and has a spring constant of 7.7 N/m. What potential energy will it have in Joules?

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The elastic potential energy stored in a spring is

(1/2) (spring constant) (distance of stretch)²

= (1/2) (7.7 N/m) (16.08 m)²

= (3.85 N/m) (258.57 m²)

= 995.5 N-m

= 995.5 joules
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