Write a number in each box to make an equation that has exactly one real solution. 3(2a+1)-a = __a + __a using the numbers 1 - 10

asked Apr 22, 2017 33.3k views

1 vote

Write a number in each box to make an equation that has exactly one real solution.

3(2a+1)-a = __a + __a

using the numbers 1 - 10

by Danah

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2 votes

3(2a+1)-a
6a+1-a→→ 6a-a equals 5a
5a+3
the number in the first box is 5 and the second box 3

Ossie answered Apr 27, 2017

by Ossie

8.1k points

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