2 Answers

Manik Sidana · Answer 1 · 2017-02-13T06:32:49+0000

Answer:

The chemical reaction is given as:

$PbI_2+2CH_3COOK\rightarrow Pb(CH_3COO)_2+2KI$

Step-by-step explanation:

When lead acetate reacts with potassium iodide it gives lead iodide and potassium as acetate as products.

The chemical reaction is given as:

$PbI_2+2CH_3COOK\rightarrow Pb(CH_3COO)_2+2KI$

According to reaction, 1 mole of lead iodide reacts with 2 moles of potassium acetate to form 1 mole of lead acetate and 2 moles of potassium iodide.

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