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Hi, can you help me answer this question please, thank you!

Hi, can you help me answer this question please, thank you!-example-1
User Tspano
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1 Answer

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given the information on the picture, since we have that n*p is greater than 10, we can use a normal distribution.

We have that the critical value for 99% confidence level is 2.58.

Next, we can find the Standard Error with the following expression:


SE=\sqrt[]{(p(1-p))/(n)}

in this case we have the following:


SE=\sqrt[]{(0.6\cdot0.4)/(160)}=00387

then, according to the margin of error formula:


ME=CV\cdot SE

where CV is the critical value, we get:


ME=2.58\cdot0.0387=0.099

therefore, the margin of error is 0.099 which is a 9.9% error

User NotABot
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