Question

Find the solution of square root x+2+4 =6 and determine if it is an extraneous solution

Answer 1

`\displaystyles \\ √( x+2) +4 = 6 \\ \\ √( x+2) = 6 - 4\\ \\ √( x+2) = 2\\ \\ \Big( √( x+2)\Big)^2 = 2^2\\ \\ x+2=4 \\ \\ x = 4-2 = \boxed{2}`