Question

A) What magnitude point charge creates a 12596.37 N/C electric
held at a distance of 0.593 m?

Answer 1

`Q = 4.9216 * 10^(-7)C`

Step-by-step explanation:

Given

`E = 12596.37 N/C`

`r = 0.593m`

Required

Determine the magnitude point charge (Q)

This question will be solved using
`the\ magnitude` of the electric field formula

`E = (kQ)/(r^2)`

Where

`k = 9 * 10^9\ Nm^2 / C^2`

Make Q the subject in
`E = (kQ)/(r^2)`

`E * r^2 = kQ`

`Q = (E * r^2)/(k)`

Substitute values for E, r and k

`Q = (12596.37 * 0.593^2)/(9 * 10^9)`

`Q = (4429.50)/(9 * 10^9)`

`Q = (492.16)/(10^9)`

`Q = 492.16 * 10^(-9)`

Express in standard form

`Q = 4.9216 * 10^2 * 10^(-9)`

`Q = 4.9216 * 10^(2-9)`

`Q = 4.9216 * 10^(-7)C`