Question

2. If a spring has a spring constant of 400 N/m, how much elastic potential

energy is stored when the spring is stretched by 0.25 m?​

Answer 1

The kinetic energy of a spring is equal to its elastic potential energy.

The elastic potential energy is 12.5N-m or 12.5 Joules.

Step-by-step explanation:

`= (1)/(2) k {x}^(2) \\ = (1)/(2) (400)( {.25)}^(2) \\ = 12.5`