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1 vote
Find the range of the function f(x)=(x+5)^2+8

2 Answers

3 votes
f(x) = x²+10x+25+8
f(x) = x²+10x+33
User Myria
by
7.4k points
4 votes
finding the vertex of the parabola
y = (x + 5)^2 + 8 the vertex is at (-5, 8)
its coefficient so the parabola turns upward so the range is [8 , inf]
User JulienV
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