Question

A trapezoid was broken into a rectangle and two equal

triangles.
The base of each triangle bis
m.
The area of the rectangle is
The area of each triangle is
m2
m2.
m2.
The area of the trapezoid is
Please help

Answer 1

For the base of the triangles, we just have to remove the 1m and divide the remaining measurement into two since they are symmetrical.

For the area of the rectangle:

Explanation:

For the area of each triangle:

For the area of the trapezoid, just combine the two areas:

4m² + 4m² = 8m²

Answer 2

Explanation:

For the base of the triangles, we just have to remove the 1m and divide the remaining measurement into two since they are symmetrical.

`5m - 1m = 4m \\ (4m)/(2) = 2m \: each`

For the area of the rectangle:

`base * height = 1m * 4m = 4 {m}^(2)`

For the area of each triangle:

`(1)/(2) base * height = (1)/(2) (2m)(4m) = 4m^(2)`

For the area of the trapezoid, just combine the two areas:

4m² + 4m² = 8m²