Question

For the functions below, determine what type of solution each equation has.

Answer 1

Okay, we have three equations:

In the first if we clear x we have:

`x=\pm\sqrt[]{-9}`

So, that is:

`x=3i,\text{ x=-3i}`

f(x) has complex solutions.

In the second if we clear x, we have:

`(x-9)^2=0`
`x-9=0`
`x=9`

g(x) has 1 real solution.

In the third if we clear x, we have:

`(x+1)^2-9=0`
`(x+1)^2=9`

`x+1=\pm\sqrt[]{9}`
`x+1=+3,\text{ x+1=-3}`
`x=2,\text{ x=-}4`

So, h(x) has 2 real solutions.