1. In order to determine a viable point on the graph, you take into account that there are no negative weeks, then, (-2,-800) is not a viable point.
Then, for the other points, you evaluate the function for the number of weeks, and verify if the number of copies coincides with the given option.
For the point (2.5 , 1000):
w = 2.5
c = 400(2.5) = 1000
Thus, the point (2.5 , 1000) is viable
For the point (6 , 1800):
w = 6
c = 400(6) = 2400
Thus, the point (6 , 1800) is not viable
For the point (8 , 3200)
w = 8
c = 400(8) = 3200
Thus, the point (8 , 3200) is viable
2. The number of weeks is represented in a good way by a whole number (option d))