Question

the radius of the base of a truncated right circular cylinder is 5 in. and its longest element is 16 in. If the slope of the top plane is 3/4, find the volume of the solid.

Answer 1

`V= (r^2\pi(h_1+h_2))/(2) \\ \\ (3)/(4) = (h_1-h_2)/(d) \\ (3)/(4) = (16-h_2)/(5) \\ 4(16-h_2)=5 * 3 \\64-4h_2=15 \\49=4h_2 \\h_2= (49)/(4)=12.25 \\ \\r= (d)/(2) \\r=2.5 \\ \\V= (r^2\pi(h_1+h_2))/(2) = (2.5^2\pi(12.25+16))/(2) =88.28 \pi`