Question

What is the standard error of the proportion if 80% of the 1,200 respondents in a yes/no survey answered "no"?

Answer 1

standard error for a sample proportion, p = 0.8, n = 1200


`SE= \sqrt{ (p(1-p))/(1200) } = \sqrt{ (0.8(1-0.8))/(1200) } \approx 0.015 * 100\%=1.15\%`