Question

Write an equation of the line that passes through point P and is parallelto the line with the given equation.P(-2, 1), 10x + 4y = -8

Answer 1

`\begin{gathered} 10x+4y=-8 \\ 4y=-10x-8 \\ y=-(10)/(4)x-2 \\ \text{The slope is m=-}(10)/(4) \\ \text{The new equation is-} \\ y-1=-(10)/(4)(x+2) \\ 4y-4=-10x-20 \\ 4y=-10x-16 \\ y=-(10)/(4)x-4\text{ (equation)} \\ \\ m=-(10)/(4) \\ b=-16 \end{gathered}`