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A gun has a muzzle speed of 80 meters per second. What angle of elevation should be used to hit an object 180 meters away? Neglect air resistance and use g=9.8m/sec2 as the acceleration of gravity. The
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May 22, 2017
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A gun has a muzzle speed of 80 meters per second. What angle of elevation should be used to hit an object 180 meters away? Neglect air resistance and use g=9.8m/sec2 as the acceleration of gravity.
The answer must be in radians.
I found: angle=1/2arcsin (180*9.8)/(80^2), but it was not correct.
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Hi. Your working equation is correct. The general equation to be used is
However, make sure that when you input this in the calculator, it is in the mode of rad.
The answer is 0.14 rad.
I hope I was able to answer your question. Have a good day.
BlueCat
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May 24, 2017
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knowing the initial velocity and angle, the horizontal range formula is given by R= V^2sin(2teta) / g, so we can get
sin(2teta)=Rg/V^2
sin(2teta)= (180 x 9.8)/ 80^2= 0.27, sin(2teta)=0.27, 2teta=arcsin(0.27)=15.66, so teta=15.66/2
teta=7.83°
Ingeniarius
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May 26, 2017
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