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The equation h=-16t^2 + 32t +9 gives the height of a ball, h, in feet above the ground, at t seconds after the ball is thrown upward. How many seconds after the ball is thrown will it reach maximum height?
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Jun 28, 2017
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The equation h=-16t^2 + 32t +9 gives the height of a ball, h, in feet above the ground, at t seconds after the ball is thrown upward. How many seconds after the ball is thrown will it reach maximum height? What is its maximum height?
Mathematics
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Maninalift
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Answer:
The maximum height is 25 m.
Explanation:
Trevor Allred
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Jun 30, 2017
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Trevor Allred
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h = - 16 t² + 32 t + 9
The maximum height is at the vertex of the parabola:
t = - b / (2 a ) = - 32 : ( - 32 ) =
1 s
The ball will reach maximum height in 1 second.
h max = - 16 * 1² + 32 * 1 + 9 = - 16 + 32 + 9 =
25 m
The maximum height is 25 m.
Ficuscr
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Jul 4, 2017
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