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Sin(a-b) = sinacosb+cosasinb for all values of a and b. True or false?

User Deyon
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It is a completely false statement that Sin(a-b) = sinacosb+cosasinb for all values of a and b. The correct option among all the options that are given in the question is the second option. i hope that this is the answer that you were looking for and the answer has actually come to your desired help.
User Ebeneditos
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1 vote
False
The actual identity is:
Sin(a - b) = Sin(A)Cos(B) - Sin(B)Cos(A)
User Lucask
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