Question

Simplify and select the answer with the appropriate restrictions for the variables.

10x^2-15x/5x^2


A.2-15x,(x_0)




B.2-3x,(x_0)




C.2x-3/x,(x_0)




D.10x-3,(x_0)

Answer 1

The answer is C.2x-3/x,(x_0)


`(10 x^(2) -15x)/(5 x^(2) ) = (2x*5x -3*5x)/(5 x^(2) )= (5x(2x-3))/(5x*x)`
5x can be canceled out, thus:

`(5x(2x-3))/(5x*x) = (2x-3)/(x)`
Since x is denominator and if denominator is 0, the terms would be undefined, then x≠ 0