Question

X=6y+30
x=3/2y
solve by substitution.

Answer 1

`x=6y+30 \\ x=(3)/(2)y \\ \\ \hbox{substitute } (3)/(2)y \hbox{ for x in the 1st equation:} \\ (3)/(2)y=6y+30 \\ (3)/(2)y-6y=30 \\ 3y-12y=60 \\ -9y=60 \\ y=-(60)/(9)=-(20)/(3)=-6(2)/(3) \\ \\ x=(3)/(2) \cdot (-(20)/(3))=-(20)/(2)=-10 \\ \\ \left \{ {{x=-10} \atop {y=-6(2)/(3)}} \right.`