Answer:
The probability that the emission is within the permissible level, given the outcome of the test is 0.9132
Explanation:
For this exercise we need to define certain events:
NP: Exceeding the permissible level of carbon emission
P: Not exceed the permissible level of carbon emission
NPT: the test said that the company exceed the permissible level
PT: the test said that the company don't exceed the permissible level
Additionally the accuracy is the probability that the test say something and that is according with reality.
From the information we have 4 possible cases with their respective probabilities:
1. the company exceed the permissible level and the test said the same: this can be calculate as the multiplication of the probability that the company exceed the permissible level (35%) and the accuracy of the test (85%), so:
P(NP y NPT)=0.35*0.85= 0.2975
2. the company exceed the permissible level and the test said the opposite: this can be calculate as the multiplication of the probability that the company exceed the permissible level (35%) and the complement of the accuracy of the test (15%), so:
P(NP y PT)=0.35*0.15= 0.0525
3. the company doesn't exceed the permissible level and the test said the same: this can be calculate as the multiplication of the probability that the company doesn't exceed the permissible level (65%) and the accuracy of the test (85%), so:
P(P y PT)=0.65*0.85= 0.5525
4. the company doesn't exceed the permissible level and the test said the opposite: this can be calculate as the multiplication of the probability that the company doesn't exceed the permissible level (65%) and the complement of the accuracy of the test (15%), so:
P(P y NPT)=0.65*0.15= 0.0975
Then the probability that the emission is within the permissible level, given the outcome of the test can be written and calculate as:

the probability of PT can be calculate as the sum of every possible case that involve PT, so:
P(PT)=P(NP y PT) + P(P y PT)
P(PT)=0.0525+0.5525 = 0.605
therefore replacing values on the initial equation we get:

P(P/PT)=0.9132
Finally, The probability that the emission is within the permissible level, given the outcome of the test is 0.9132