Answer: D is the correct option. The constant part of the trinomial will be equal to the product of p and q.
Explanation:
Given: Two binomials (x+p)and (x+q) such that they are multiplied to form a quadratic trinomial
![(x+p)(x+q)=x(x+q)+p(x+q)\text{[......distributive law]}\\\\=x^2+px+qx+pq\text{[........distributive law]}\\=x^2+(p+q)x+pq\text{[......combine like terms]}](https://img.qammunity.org/2017/formulas/mathematics/high-school/59y7a4g34ykeqf5shf5nul2ujqqyqthrqv.png)
Here we can see the trinomial with three terms where first term is
,second term is (p+q)x and third term is the constant term with product of p and q.
Therefore, the constant part of the trinomial will be equal to the product of p and q.