(Pi value = 3)
Given diameter of circle = 12 inches
Radius of circle :
![= \tt(diameter)/(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/6x91t7rm47eubfv8w5vepj2cdavk4l7rut.png)
![= \tt(12)/(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/oh81u95a0al6b7funmm2fftw8i670usgst.png)
![= \tt6 \: inches](https://img.qammunity.org/2022/formulas/mathematics/high-school/5cg9b5ch2jrz1by2zwpbvfxsrr1y4biont.png)
Thus, the radius of this circle = 6 inches
Circumference of this circle :
![= \tt2\pi r](https://img.qammunity.org/2022/formulas/mathematics/high-school/dty3rfohvucsvputy19euzye1qgvwzyqdj.png)
![=\tt 2 * 3 * 6](https://img.qammunity.org/2022/formulas/mathematics/high-school/ie090709cltbgt29wfdr1xd3j8b669dr90.png)
![= \tt36 \: inches](https://img.qammunity.org/2022/formulas/mathematics/high-school/zwgev7fubjzq2uj2rqty5gfxmrr3rxmopl.png)
Thus, the circumference of this circle = 36 inches
The area of this circle :
![= \tt\pi {r}^(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/bupd3cs51hjlujker11fpzza2mcof81vpq.png)
![=\tt 3 * 6 * 6](https://img.qammunity.org/2022/formulas/mathematics/high-school/tgfdyixxg1rj7n4r7wshvn2iqvtxdffr8m.png)
![= \tt108 \: {inches}^(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/eoygy7bir7upy33pqk2sj2syzbusyja3na.png)
Thus, the area of this circle = 108 inches²
Therefore,
Radius = 6 inches
Diameter = 12 inches
Circumference = 36 inches
Area = 108 inches²