Question

A juggler is performing her act using several balls. She throws the balls up at an initial height of 4 feet, with a speed of 15 feet per second. If the juggler doesn't catch one of the balls, about how long does it take the ball to hit the floor?

Hint: Use H(t) = _16t2 + vt + s.

7.52 seconds
1.15 seconds
0.47 second
0.22 second

Answer 1

The ball will take 1.15 seconds to hit the floor.

Step-by-step explanation:

It is given that,

A juggler is performing her act using several balls. The height as a function of time is given by :

`h(t)=-16t^2+vt+s`.............(1)

where

v is the speed of the ball

s is initial height

t is time taken

Putting h(t) = 0 and solving equation (1)

`-16t^2+vt+s=0`

`-16t^2+15t+4=0`

On solving above equation using graphing calculator and solving for t we get, t = 1.154 seconds

Hence, the correct option is (b) " 1.15 seconds ".

Answer 2

The correct answer between all the choices given is the second choice, which is 1.15 seconds. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.