Question

emeril used a total of 7 1/4 cups of flour to make three pastries. he used 2 1/4 cups of flour for the first and 2 1/3 cups for the second. how much flour did emeril use for the third pastry?

Answer 1

2 1/3 + 2 1/4
= 4 7/12
7 1/4 - 4 7/12
=2 2/3

Answer 2

2 2/3 cups of flour

Explanation:

The question records that Emeril used a total of 7 1/4 cups of flour for three pastries.

For the first pastry, he used 2 1/4 cups of flour

For the second pastry, he used 2 1/3 cups of flour

To get how much of flour be used for the third, we add the amount he used for the first and second together and subtract that sum from the total cups of flour.

That is, 2 1/4 + 2 1/3

To add this mixed fractions, we add the whole number part first to get: 4 1/4 + 1/3

We then find the L.C.M of 4 and 3 (denominators), which is 12 and solve to get 4 7/12.

4 7/12 is the sum of the two pastries, we then subtract it from 7 1/4 i.e. 7 1/4 - 4 7/12 = 2 8/12

2 8/12 can be broken down to its simplest form which is 2 2/3.

Hence, the amount of flour used for the third pastry by Emeril is 2 2/3 cups