Question

How many moles are in 1.2x10^3 grams of ammonia(NH3) ?

Answer 1

Molar mass NH3 = 17.031 g/mol

1 mole NH3 ---------- 17.031 g
?? moles -------------- 1.2x10³ g

moles NH3 = 1 x ( 1.2x10³ ) / 17.031

moles NH3 = 1.2x10³ / 17.031

= 70.45 moles of NH3

hope this helps!

Answer 2

Answer : The number of moles present in ammonia is, 70.459 moles.

Solution : Given,

Mass of ammonia =
`1.2* 10^3g`

Molar mass of ammonia = 17.031 g/mole

Formula used :

`\text{Moles of }NH_3=\frac{\text{ given mass of }NH_3}{\text{ molar mass of }NH_3}`

`\text{Moles of }NH_3=(1.2* 10^3g)/(17.031g/mole)=70.459moles`

Therefore, the number of moles present in ammonia is, 70.459 moles.