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Find the vertex for quadratic function y=2x^2-20x+10

User Sri Sris
by
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1 Answer

7 votes
2x^2 - 20x = y - 10
x^2 - ( 20/4 )^2 + ( 20/4 )^2 = y - 10
( x - 5 )^2 = y - 10 - 25
( x - 5 )^2 = y - 35
Vertex = ( 5 , 35 )

i am a mathematics teacher. if anything to ask please pm me
User Mianos
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