42.8k views
2 votes
Find the vertex for quadratic function y=2x^2-20x+10

User Sri Sris
by
7.7k points

1 Answer

7 votes
2x^2 - 20x = y - 10
x^2 - ( 20/4 )^2 + ( 20/4 )^2 = y - 10
( x - 5 )^2 = y - 10 - 25
( x - 5 )^2 = y - 35
Vertex = ( 5 , 35 )

i am a mathematics teacher. if anything to ask please pm me
User Mianos
by
8.4k points