Find the vertex for each quadratic equation y=3x^2-24x+47

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asked May 24, 2017 232k views

1 Answer

Isaac Weathers · Answer 1 · 2017-05-28T01:22:50+0000

3x^2 - 24x = y - 47
x^2 - ( 24/6 )^2 + ( 24/6 )^2 = y - 47
( x - 4 )^2 = y - 47 - 16
( x - 4 )^2 = y - 63
Vertex = ( 4 , 63 )

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Find the vertex for each quadratic equation y=3x^2-24x+47

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