39.3k views
5 votes
A garden has a perimeter of 120 feet. The difference between the length and twice the width is 24 feet. Write a system of linear equations that represents his situation. Then solve the system to find the length and width of the garden.

1 Answer

6 votes

Lets say the length is x and the width is y.

The perimeter is calculated by using 2x +2y=120 and we know that the difference of x and twice y is 24, x-2y=24 so, lets use this and solve for x.

Add 2y to both sides and get x=2y+24. Now we can use substitution into the perimeter equation because we know what x equals.

2(2y+24) +2y=120 Now solve for Y.

4y+48+2y=120

6y+48=120

6y=72

y=12 Your width is 12feet. Now use twelve in your perimeter equation and solve for X

2x+2y=120 so,

2x +2(12)=120

2x+24=120 subtract 24 from both sides

2x=96 divide by 2

x=48 your length is 48 meters.

User Rugolinifr
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories