Question

Find h if the perimeter of the polygon is 33..

Answer 1

Okay, here we have this:

Considering the provided information, and that the perimeter is the sum of all the sides, we obtain that:

`2h+1+h+2+h+1+3+2\mleft(h+1\mright)=33`

Now, let's solve for h:

`\begin{gathered} 2h+h+h+2\mleft(h+1\mright)+1+2+1+3=33 \\ 4h+2\mleft(h+1\mright)+1+2+1+3=33 \\ 4h+2\mleft(h+1\mright)+1+2+1+3-\mleft(1+2+1+3\mright)=33-\mleft(1+2+1+3\mright) \\ 4h+2\mleft(h+1\mright)=26 \\ 4h+2h+2=26 \\ 6h+2=26 \\ 6h=24 \\ h=(24)/(6) \\ h=4 \end{gathered}`

Finally we obtain that the correct answer is the option A.