Question

(03.01) Which of the following is a factor of x2 − 6x − 27? (1 point) Select one: a. x + 3 b. x + 9 c. x − 1 d. None of the above

Answer 1

`{x}^(2) - 6x - 27 \\ factorise \\ {x}^(2) - 9x + 3x - 27 \\ = take \: x \: from \: first \: two \: terms \\ and \: 3from \: last \: two \: terms \\ then \\ x(x - 9) + 3(x - 9) \\ here(x - 9)is \: commen \\ so(x - 9)(x + 3) \\ (1)is \: ur \: answer \: it \: is \: x + 3 \\ thank \: you`

Answer 2

Answer:-

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`\pink{\bigstar}` The factor of given expression is
`\large\leadsto\boxed{\tt\purple{Option.a \rightarrow (x+3)}}`

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• Given:-

✯ x² - 6x - 27

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• Solution:-

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• Splitting the middle term:-

➪ x² - 9x + 3x - 27

➪ x(x - 9) + 3(x - 9)

★ (x -9) (x +3)

Therefore, the factors of the given expression are (x - 9) and (x +3).

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Hence, Option A. i.e (x + 3) is the correct choice.