Solve 4sin2θ + 4cosθ - 5 = 0 for 0° ≤ θ < 180°. Ø 0° 30° 60°

Qammunity

My account
Edit my Profile
Private messages
My favorites

Ask a Question
Questions
Unanswered
Tags
Categories
Ask a Question

asked Aug 15, 2017 183k views

3 votes

Solve 4sin2θ + 4cosθ - 5 = 0 for 0° ≤ θ < 180°.
Ø
0°
30°
60°

Mathematics
high-school

MGZero asked

by MGZero

7.2k points

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

4 votes

the answer is 60 or 300

Gibatronic answered Aug 22, 2017

by Gibatronic

8.2k points

0 Comments

Please log in or register to add a comment.

← Prev Question Next Question →

Related questions

asked Mar 20, 2018 99.9k views

The height H in feet above the ground of the seat of a playground swing can be modeled by H(θ) = -4cosθ + 6, where θ is the angle the swing makes with a vertical extended to the ground. Graph the height

Marek Dominiak asked Mar 20, 2018

by Marek Dominiak

7.9k points

Mathematics
high-school

1 answer

0 votes

99.9k views

asked Oct 28, 2020 173k views

The letters r and Θ represent polar coordinates. perform the following. r = 5/r-4cosΘ cross multiply then convert the polar equation to rectangular form

Jeff Perrin asked Oct 28, 2020

by Jeff Perrin

7.3k points

Mathematics
middle-school

1 answer

3 votes

173k views

asked Jun 4, 2020 56.3k views

Convert the Cartesian equation (x 2 + y 2)2 = 4(x 2 - y 2) to a polar equation. Choices: r4 = -4r2 r2 = 4cos2θ r2 = 4sin2θ

Kirbo asked Jun 4, 2020

by Kirbo

8.4k points

Mathematics
middle-school

1 answer

3 votes

56.3k views

Ask a Question

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

0 Comments

Please log in or register to add a comment.

Related questions

Other Questions