Question

The length of a rectangle is nine inches less than twice the width If the perimeter of the rectangle is 84 inches find the dimensions of the rectangle

Answer 1

width is 17, while length is 25

Answer 2

Dimensions of the rectangle are 25 inches × 17 inches.

Explanation:

Let the length of the rectangle = l inches and width = w inches

The length of the rectangle is 9 inches less than twice the width.

Therefore, l = (2w - 9)

Perimeter of the rectangle is = 84 inches

And perimeter of the rectangle = 2(Length + width)

= 2(l + w)

= 2[(2w - 9) + w]

= 2[3w - 9]

Now 84 = 2{3w - 9)

3w - 9 =
`(84)/(2)`

3w - 9 = 42

3w = 42 + 9

3w = 51

w =
`(51)/(3)`

w = 17 inches

Since l = 2w - 9

l = 2×17 - 9

= 34 - 9

= 25 inches

Therefore, dimensions of the rectangle are 25 inches × 17 inches.