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After 8 yr there will be ?g of a radioactive substance

After 8 yr there will be ?g of a radioactive substance-example-1
User Stombeur
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1 Answer

14 votes
14 votes

\begin{gathered} 9=18e^(-3k) \\ 0.5=e^(-3k) \\ ln(0.5)=-3k \\ k=-(ln(0.5))/(3)=0.23105 \end{gathered}

Thus;


\begin{gathered} A=18e^(-0.23105*8) \\ A=2.835 \end{gathered}

Thus, the remaining amount is 2.835 g