Question

-|14-6(1)+7(-6+2(-2)|

Answer 1

The given expression is

`-\lvert14-6n+7(q+2t)\rvert`

n = 1, q = -6, and t = -2

`-\lvert14-6(1)+7\lbrack(-6)+2(-2)\rbrack\rvert=`

Simplify the square bracket

`\begin{gathered} -\lvert14-6+7\lbrack-6+(-4)\rbrack\rvert= \\ -\lvert14-6+7\lbrack-10\rbrack\rvert= \end{gathered}`

Multiply 7 by -10

`\begin{gathered} -\lvert14-6+(-70)\rvert= \\ -\lvert14-6-70\rvert= \end{gathered}`

Add all terms

`-\lvert14-6-70\rvert=-\lvert-62\rvert`

The absolute value will cancel the negative of 62 (I-62I = 62)

`-\lvert-62\rvert=-62`

The answer is -62